what is the mole fraction of a solute in 2.5 m aqueous solution?
Answers
2.5 molal aqueous solution means 2.5 moles of solute in 1 kg solvent
⇒ moles of solute=2.5
moles of water=1000/18=55.55
so mole fraction = 2.5/(2.5+55.55)=.043
Answer: The mole fraction of the solute in a 2.5 molal aqueous solution would be 0.043.
The mole fraction of a solute in a solution is a measure of the concentration of the solute relative to the total number of moles of solute and solvent in the solution. It provides a way of expressing the relative amounts of solute and solvent in a solution.
In a 2.5 molal aqueous solution, 2.5 moles of solute are dissolved in 1 kilogram (1000 grams) of water, which is equivalent to 55.55 moles of water.
To calculate the mole fraction of the solute, we divide the moles of solute by the total moles of solute and solvent:
mole fraction = 2.5 moles / (2.5 moles + 55.55 moles)
mole fraction = 0.043
So, the mole fraction of the solute in a 2.5 molal aqueous solution is 0.043, which means that 0.043 of the total moles in the solution are due to the solute, and the rest (0.957) is due to the solvent (water).
It's important to note that the mole fraction is different from other concentration units, such as molarity (moles per liter) or molality (moles per kilogram), as it takes into account both the solute and the solvent.
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