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the no of sample events will be 36
suresh274:
how bro
Check my solution below.
when ever 2 dive are thrown then suppose in 1st throw some no came and in second throw some other no came....!.there is possibility of getting 6 numbers in 1st throw as well as in 2 nd throw .... total no of sample space is combination of no that came in 1st throw and second throw...so it is 6x6=36
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If a dice is thrown twice, let S denote the Sample Space
A dice has 6 sides, it's thrown twice hence - each possibility will be represented in two throws (Throw 1, Throw 2);
The sample space in this instance is:
S = {(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),
(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),
(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),
(4,1,),(4,2),(4,3),(4,4),(4,5),(4,6),
(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),
(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}
Here, number of elements in the Sample Space can be denoted by n(S)
Therefore, n(S) = 36 elements
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