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How to draw an isosceles triangle with base 6cm and vertical angle 30°?
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Let consider an isosceles triangle ABC,
It is given that, base is 6 cm and whose Vertical angle is 72 degree
Let vertical angle be A = 72 and base BC = 6cm
Base angles, <B and <C are equal
Therefore sum of base angle = 180 - 72 = 108
<B = <C = 108/2 = 54°
Construction of triangle ABC
Step 1: Draw a line segment say BC = 6cm
Step 2: From B draw line BX making angle 54° with BC
Step 3: From C draw line CY making angle 54° with BC
Step 4: Mark the point of intersection of BX and CY as A
So triangle ABC is an isosceles triangle whose base is 6 cm and whose Vertical angle is 72 degree
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