Question

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Answer 1

$Volume of cylinder B is greater than that of cylinder A.\\We use the formulae: \\V = pi r^2h\\S=2pi r(r+h)\ where,\\V=volume\ of\cylinder\ S=surface\of\ ylinder\r=\ radius\ h=heightCylinder A:\V=pi r^2h => V= 22/7 * (7/2)^2 * 14=540\\S=2pi r(r+h) =>S = 2 * 22/7 * 7/2 * (7/2 + 14) =385\\Cylinder B:V=pi r^2h => V = 22/7 * (14/2)^2 * 7 = 1028\\S=2pi r(r+h) => S=2 * 22/7 * 14/2 * (14/2 + 7) = 616\\Hence,\ It's\ clear\that,\ cylinder\ with\ greater\ volume\ has\ greater\ surface\ area\ cylinder\ B$

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