Question

please help me. factorisation ​

Answer 1

Answer is given in the above picture. Hope it helps.

Answer 2

Step-by-step explanation:

Given :-

x^2+(1/x^2) -11

To find :-

Factorization of the expression ?

Solution :-

Given expression is x^2+(1/x^2) -11

=> x^2+(1/x^2)-2-9

=> (x)^2 +(1/x)^2-2(x)(1/x)-9

=> [x-(1/x)]^2-9

Since a^2-2ab+b^2 =(a-b)^2

Where a = x and b = 1/x

=] [x-(1/x)]^2 -(3)^2

This is in the form of a^2-b^2

Where a = x-(1/x) and b=3

We know that

a^2-b^2 = (a+b)(a-b)

=> [x-(1/x)+3][x-(1/x)-3]

Answer:-

The factorization of x^2+(1/x^2)-11 is

[x-(1/x)+3][x-(1/x)-3]

Used formulae:-

• a^2-2ab+b^2 =(a-b)^2

• a^2-b^2 = (a+b)(a-b)