Question

please help me factorising it.

Answer 1

$\huge\underline\mathfrak{Subject}$

Math


$\huge\underline\mathfrak{Topic}$

Factorising



$\textbf{Step-by-Step-Solution}$

Given equation

${x}^{2} + \frac{1}{ {x}^{2} } + 2 = 0$

${x}^{4} + 1 + 2 {x}^{2} = 0$



Rearrange this Equation

${x}^{4} + 2 {x}^{2} + 1 = 0$

${ ({x}^{2}) }^{2} + {1}^{2} + 2 {x}^{2} + = 0$

$a = {x}^{2}$

$b = {1}^{2}$

$\textbf{Using,Formula}$

$( {x + y})^{2} = {x}^{2} + {y}^{2} + 2xy$

we can write it

${( {x}^{2} + 1) }^{2} = 0$



$\textbf{Factores}$

$( {x}^{2} + 1) \: \: \: ( {x}^{2} + 1)$




$\huge\underline\mathfrak{Hence}$

Factores are

$( {x}^{2} + 1) \: \: \: ( {x}^{2} + 1)$