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I think in case 1&3 ZnSO4 and FeSO4 will be formed respectively. so it leaves us with options 2&4
and anyhow in opt2
ZnCl2 will be formed so H2 gas will be released
and in opt 4
NaAlO2 will be formed and H2 gas will be released so 2&4 is the correct option
hope it helps
and anyhow in opt2
ZnCl2 will be formed so H2 gas will be released
and in opt 4
NaAlO2 will be formed and H2 gas will be released so 2&4 is the correct option
hope it helps
kumar3398:
thank you
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