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Answers
this is the required answer
NOTE: -1 and 1 should not be included in the answer as they make the inequality undefined. that is why I used open brackets (,)
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Answer:
Domain of h(x) =(−∞,−1]∪[1,4]
Explanation:
Domain is all possible allowable x value inputs.There are generally 2 cases that are not allowed in real functions :Even square roots of negative numbers. (Not defined in R).
Division by zero. (Not defined at all).
In this case there are no divisions (denominators) in h(x)
so we only consider case 1 of the square roots not allowed to be negative.Doing so, it becomes clear that the first term is only negative if x>4 and the second term is only negative if x<1.
So #Hence the domain is {x∈R∣−∞<x≤1and1≤x≤4}=(−∞,−1]∪[1,4].
The graph makes it clear :graph{sqrt(4-x)+sqrt(x²-1) [-7.28, 10.5, -1.93, 6.95]}
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