Question

please help me fastly please​

Answer 1

Answer:

 x = -1/7 , y = 19/7

Step-by-step explanation:

$25^x^+^1 = 5^{y-1} \\(5^2)^x^+^1 = 5^{y-1} \\5^{2x+2} = 5^{y-1} \\ 2x+2 = y - 1\\2x - y = - 1 - 2\\2x - y = -3 >> eq1$

$(32)^y = 4 * 8^x\\(2^5)^y = (2^2) * (2^3)^x\\2^5^y = 2^{2} * 2^3^x\\ 2^5^y = 2^{2+3x}\\5y = 2+3x\\3x-5y=-2 >> eq2$

eq 1 x 5 -----> 10x - 5y = -3

                       3x - 5y = -2

                    ___________

(subtract)        7x = -1

                        x = -1/7

sub x=-1/7 in eq1

2x - y = -3

2(-1/7) - y = -3

-2/7 + 3 = y

y = 19/7

Answer 2

Answer:

x = -13/7 & y = -5/7

Step-by-step explanation:

eq (i) 2x-y = -3

eq (ii) 3x-5y = -2