Question

please help me fasttttt​

Answer 1

Here

$\\ \sf\longmapsto 3x-38=2x+10$

$\\ \sf\longmapsto 3x-2x=10+38$

$\\ \sf\longmapsto x=48$

Now

$\\ \sf\longmapsto y=2x+10$(Opposite angles)

$\\ \sf\longmapsto y=2(48)+10$

$\\ \sf\longmapsto y=96+10$

$\\ \sf\longmapsto y=106$

Answer 2

$in \: this \: figure \: (3x - 38) \: and \: (2x + 10) \: are \: corresponding \: angles \\ which \: means \: both \: are \: equal \\ 3x - 38 = 2x + 10 \\ = 3x - 2x = 10 + 38 \\ x = 48 \\ \\ \\ inputting \: value \: of \: x \: in \: 2x + 10 = 96 + 10 = 106 \\ angle \: y \: is \: opposite \: of \: 2x + 10 \: that \: means \: angle \: y \: \\ \maltese \: \huge \fbox \green {y \: = 108}$