Math, asked by rohanraj8487, 3 months ago

Please help me find out the answer I am request you to find out the answer if you don't know the answer don't answer it and do all questions please ​

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Answered by sudhanshudhek76
4

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Since

Since we know the Angle sum property of triangle and a quadrilateral i.e 180° & 360° respectively.

ACC. TO FIGURE

 \angle5 +  \angle1 +  \angle2 = 180 \\  \\ and \\  \\  \angle2 +   \angle3 +  \angle4 +  \angle5 = 360

equating both the equation we get

angle 1 + angle 2 + angle 3 + angle 4 + angle 5 = 180° + 360° = 540°

Answered by SaanviMishra
2

Answer:

Since

SinceSince we know the Angle sum property of triangle and a quadrilateral i.e 180° & 360° respectively.

SinceSince we know the Angle sum property of triangle and a quadrilateral i.e 180° & 360° respectively.ACC. TO FIGURE

SinceSince we know the Angle sum property of triangle and a quadrilateral i.e 180° & 360° respectively.ACC. TO FIGURE\begin{gathered} \angle5 + \angle1 + \angle2 = 180 \\ \\ and \\ \\ \angle2 + \angle3 + \angle4 + \angle5 = 360\end{gathered}

SinceSince we know the Angle sum property of triangle and a quadrilateral i.e 180° & 360° respectively.ACC. TO FIGURE\begin{gathered} \angle5 + \angle1 + \angle2 = 180 \\ \\ and \\ \\ \angle2 + \angle3 + \angle4 + \angle5 = 360\end{gathered} ∠5+∠1+∠2=180

SinceSince we know the Angle sum property of triangle and a quadrilateral i.e 180° & 360° respectively.ACC. TO FIGURE\begin{gathered} \angle5 + \angle1 + \angle2 = 180 \\ \\ and \\ \\ \angle2 + \angle3 + \angle4 + \angle5 = 360\end{gathered} ∠5+∠1+∠2=180and

SinceSince we know the Angle sum property of triangle and a quadrilateral i.e 180° & 360° respectively.ACC. TO FIGURE\begin{gathered} \angle5 + \angle1 + \angle2 = 180 \\ \\ and \\ \\ \angle2 + \angle3 + \angle4 + \angle5 = 360\end{gathered} ∠5+∠1+∠2=180and∠2+∠3+∠4+∠5=360

SinceSince we know the Angle sum property of triangle and a quadrilateral i.e 180° & 360° respectively.ACC. TO FIGURE\begin{gathered} \angle5 + \angle1 + \angle2 = 180 \\ \\ and \\ \\ \angle2 + \angle3 + \angle4 + \angle5 = 360\end{gathered} ∠5+∠1+∠2=180and∠2+∠3+∠4+∠5=360

SinceSince we know the Angle sum property of triangle and a quadrilateral i.e 180° & 360° respectively.ACC. TO FIGURE\begin{gathered} \angle5 + \angle1 + \angle2 = 180 \\ \\ and \\ \\ \angle2 + \angle3 + \angle4 + \angle5 = 360\end{gathered} ∠5+∠1+∠2=180and∠2+∠3+∠4+∠5=360

SinceSince we know the Angle sum property of triangle and a quadrilateral i.e 180° & 360° respectively.ACC. TO FIGURE\begin{gathered} \angle5 + \angle1 + \angle2 = 180 \\ \\ and \\ \\ \angle2 + \angle3 + \angle4 + \angle5 = 360\end{gathered} ∠5+∠1+∠2=180and∠2+∠3+∠4+∠5=360 equating both the equation we get

SinceSince we know the Angle sum property of triangle and a quadrilateral i.e 180° & 360° respectively.ACC. TO FIGURE\begin{gathered} \angle5 + \angle1 + \angle2 = 180 \\ \\ and \\ \\ \angle2 + \angle3 + \angle4 + \angle5 = 360\end{gathered} ∠5+∠1+∠2=180and∠2+∠3+∠4+∠5=360 equating both the equation we getangle 1 + angle 2 + angle 3 + angle 4 + angle 5 = 180° + 360° = 540°

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