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Answers
Answer:
1.i) Exterior; Interior
2.i) Interior;ii) exterior;iii) 180°;iv)Two opposite interior angles of the ∆ ;v) right angled triangle
3.i) 120°, 40°, 20°;ii) 50°
4. CDB=80°, DBC=55°, ABC=90°
1. state whether it's ' exterior angle ' or ' interior angle '
A. Exterior angle
B. Interior angle
2. Answer in one word
A. Interior angle
B. Exterior angle
C. 180°
D. Two interior angles
E. Right angle triangle
3. Find Values
A.
Solution :-
In ∆ ABC
Given :-
Angle A = 6x
Angle B = 2x
Angle C = x
6x+2x+x=180° ( A.S.P or Angle Sum Property )
9x=180°
x=180/9
x=20
So, X = 20
Finding Value Of angle A :-
6x
= 6 × x
= 6 × 20
= 120°
Finding Value of angle B :-
2x
= 2 × x
= 2 × 20
= 40°
Finding Value Of angle C :-
X
= X = 20 °
B.
Solution :-
In ∆ PQR
( there was Is name in this triangle so you can name it )
Given :-
Angle A = 100°
Angle B = Let's suppose it as X
Angle C = 30°
100°+x+30°=180° ( A.S.P or Angle Sum Property )
100°+30°+x=180°
130°+x=180°
x=180°-130°
x = 50
Finding Value of angle B :-
X
x= 50°
4.Find Angles
In ∆ ABC
First, We will find Angle B :-
40°+100°+B=180°( A.S.P Or Angle Sum Property)
140°+B=180°
B=180°-140°
B=40°
In ∆ CDB
Now, we will find Angle D
180°-100° = D ( Linear Pair )
80° = D
In ∆CDB
Now, we will find Angle B
45°+80°+B=180°( A.S.P Or Angle Sum Property)
125°+B=180°
180°-125°=B
55°=B