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probability....
sum=7
3+4,2+5,6+1 ..............
sum perfect square
2+2=4=2^2,6+3=9=3^2,5+4=9=3^2.........
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PROBABILITY :-
(1,1)(1,2)(1,2)(1,3)(1,3)(1,4)
(2,1)(2,2)(2,2)(2,3)(2,3)(2,4)
(3,1)(3,2)(3,2)(3,3)(3,3)(3,4)
(4,1)(4,2)(4,2)(4,3)(4,4)
(5,1)(5,2)(5,2)(5,3)(5,3)(5,4)
(6,1)(6,2)(6,2)(6,3)(6,3)(6,4)
1.]
PROBABILITY OF GETTING SUM 7
(3,4)(4,3)(5,2)(6,1) = 4 / 36 = 1/9
2.]
PROBABILITY THAT SUM IS A PERFECT SQUARE
(1,3)(1,3)(2,2)(2,2)(3,1)(5,4)(6,3)(6,3) = 8 / 36 = 2/9
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