Question

Please help me find question no. 6

Answer 1

here is your answer buddy...

Angle PAR = 90°
AR=8 cm
AP=6 cm
so, According to the Pythagoras theorism
the length of PR cm will be -----
$\sqrt{ {8}^{2} + {6}^{2} } \: cm \\ = \sqrt{64 + 36} \: cm \\ = \sqrt{100 } \: cm \\ = 10cm$
PR=10cm
PQ=24cm
QR=26cm
so,
$= \sqrt{ {24}^{2} + {10}^{2} } \\ = \sqrt{576 + 100} \\ = \sqrt{676} \: cm \\ = 26cm$
so PQ^2+PR^2=QR^2
hence the Pythagoras theorism is applicable for the triangle ∆PQR
So the angle QPR=90°【Answer】
Hope it helps..