Question

please help me friends

Answer 1

Answer:

1.4416 kg

Explanation:

Given :

• The ascending acceleration of the lift = 0.6 m/s²
• Mass of the parcel which is hung from the spring balance = 13.6 N = 1.36 kg
• Acceleration due to gravity = g = 10 m/s²

To find :

• Reading in spring balance

When the lift is ascending the acceleration of lift will add on to the acceleration due to gravity

Acceleration due to ascending = 10+0.6

Acceleration due to ascending = 10.6 m/s²

Weight = mass × acceleration

Weight = 1.36 × 10.6

Weight = 14.416 Newtons

Mass = 1.4416 kg

The reading in the spring balance will be equal to 1.4416 kg

Answer 2

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✰Question ✰

▪ A lift is ascending with an acceleration of 0.6m/ s².A man hold a spring balance from which a parcel weighing 13.6N is hung . what will be the reading in spring balance. (g=10m/s²).

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Given :-

• Ascending acceleration =0.6m/s²

• Weight of parcel =13.6N

∴ Mass =13.6/10=1.36kg.

• Acceleration due to gravity =10m/s²

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To Find:-

• Reading in Spring balance.

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Solution :-

• Acceleration due to ascending =10+0.6

• Acceleration due to ascending =10.6m/s²

We know that,

weight is the product of mass and acceleration.

☛ Weight =mass × acceleration

☛ W =m×a

☛ W =1.36×10.6

☛ W =14.416N

∴The reading in the spring balance is equal to 14.416N.