Question

Please help me friends. ​

Answer 1

Answer:

3a+2b+2√6ab

this is the answer

Answer 2

Answer:

3a² + 2b² + 2√6ab

How to solve?

We will solve this question by using identify ( a + b )² , then by following proper steps we can easily calculate it.

( a + b )² = a² + b² + 2ab

Step-by-step explanation:

✰ ( √3a + √2b )²

Using identify,

➟ ( √3a )² + ( √2b )² + 2 × √3a × √2b

Now, √ gets cancel with ² whereas a gets multiplied by ² , as

( √3 )²

√3 × √3 = 3

( a )² = a²

➟ 3a² + ( √2b )² + 2 × √3a × √2b

Now again, √ gets cancel with ² whereas b gets multiplied by ² , as

( √2 )²

√2 × √2 = 2

( b )² = b²

➟ 3a² + 2b² + 2 × √3a × √2b

Now, multiply both the coefficients in sq roots (√3 × √2 ) first, then their variables and at last number 2, as

√3 × √2 = √6

a × b = ab

So, √6ab

2 × √6ab = 2√6ab

➟ 3a² + 2b² + 2√6ab Ans.

More Identities:

➩ ( a - b )² = a² + b² - 2ab

➩ ( a + b )² + ( a - b )² = 2(a² + b²)

➩ ( a + b )² - ( a - b )² = 4ab

➩ ( a + b )³ = a³ + b³ - 3ab ( a + b )

➩ ( a - b )³ = a³ - b³ - 3ab ( a - b )

▬▬▬▬▬▬▬▬▬▬▬▬▬▬