Question

Please help me guys ​

Answer 1

Answer:

this was also my doubt but I am also trying to do it

Answer 2

Step-by-step explanation:

$OP \: is \: the \: bisector \: of \: \angle BOC \\ \therefore \angle \: 1 = \angle \: 2 .....(1) \\ OQ \: is \: the \: bisector \: of \: \angle AOC \\ \therefore \angle \: 4 = \angle \: 3 .....(3) \\ \angle AOC + BOC = 180 \degree ..(linear \: pair \: angle) \\ \implies \angle \: 1 + \angle \: 2 + \angle \: 3 + \angle \: 4= 180 \degree \: ...(3) \\ from \: equations \: (1), (2) \: and \: (3) \: we \: find : \\ \angle \: 2 + \angle \: 2 + \angle \: 3 + \angle \: 3= 180 \degree \\ 2\angle \: 2 + 2\angle \: 3= 180 \degree \\ 2( \angle \: 2 + \angle \: 3)= 180 \degree \\ \angle \: 2 + \angle \: 3 = 90 \degree \\ \implies \: \angle \: 1 + \angle \: 4 = 90 \degree \\ \implies \: \angle \: POQ = 90 \degree$