Question

please help me I will mark you as a brain list

Answer 1

Total no. moles required-

$molarity \times volume \\ 0.25 \times 2.5 \\ moles = \frac{5}{8} \\ moles = \frac{mass}{molarmass} \\ \frac{5}{8} = \frac{mass}{32} \\ mass = 40g$

We get mass 40gm

simply use formula

$density = \frac{mass}{volume}$

put mass =40gm

Get your volume simply...

Answer 2

Answer:

Explanation:

Well, first off we calculate the required molar quantity of methanol....

Explanation:

And since

concentration

=

moles of solute

volume of solution

...if we gots a

2.5

⋅

L

volume of its

0.25

⋅

m

o

l

⋅

L

−

1

solution.....then we got a molar quantity of....

0.25

⋅

m

o

l

⋅

L

−

1

×

2.5

⋅

L

=

0.625

⋅

m

o

l

with respect to

methanol

.

And thus a mass of

0.625

⋅

m

o

l

×

32.04

⋅

g

⋅

m

o

l

−

1

=

20.0

⋅

g

with respect to methanol.

And so we need a volume of

20.0

⋅

g

793

⋅

g

⋅

L

−

1

=

0.0253

⋅

L

≡

25.25

⋅

m

L

.