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Since (x-1) and (x+3) are factors
×-1=0
x=1
x+3=0
x=-3
1^3-a(1^2)-13(1)+b=0
1-a-13+b=0
14-a+b=0
a-b=14. -i
(-3)^3-a(-3^2)-13(-3)+b=0
-27-9a+39+b=0
12-9a+b=0
9a-b=12. -ii
Subtracting i from ii
9a-b-a+b=12-14
8a=-2
a=-1/4
b=-57/4
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