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cot(sinx) is not defined for which sinx = 0
because cotx is not defined for x=0 , it value approaches to ∞
therefore sinx = 0 for x∈nπ
hence cot(sinx) is not defined for x = nπ
hope my ans is correct.......if so mark it as brainliest
because cotx is not defined for x=0 , it value approaches to ∞
therefore sinx = 0 for x∈nπ
hence cot(sinx) is not defined for x = nπ
hope my ans is correct.......if so mark it as brainliest
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