Question

When a bullet is fired at an angle of 15 degree with the horizontal it is hitting the ground 20 metres before the position of the target if the bullet is fired at some velocity at 45° with the horizontal it is falling out after that I get the distance from which Bullet is fired

Answer 1

Hello sir , 

here bullet is fired at 15 ° sir  and hitting the ground at 20 meters sir , 

here it is mentioned that sir , position of the target if the bullet is fired at 45 

and here it is mentioned that distance is 20 meters sir 

and sir I think its range is 20 meters 

so sir we will use the formula of range to find velocity 

sir this is the formula which is used to find the velocity 

R= u^2sin2Ф/g which means R = 20 meters  ∅ = 45° g= 10 m/s^2 

20 = u² sin (45×2) /10 which means 

200= u²sin90 

as sin(90°) = 1 

we get u = √200 

which means sir u = 10√10 m/s 

HOPE THIS HELPS YOU SIR , 

regards brainly helper