A man on tge road is just 9 meters behind the entrance door of a train when the train begins to take motion from rest with uniform acceleration of 2m/s^2. The man immediately starts running with full speed(uniform) to get into the train.He is just not able to get in. Find the speed of his running.
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hello sir ,
we will solve this question with the concept of relative motion sir , now follow
my steps sir what i am doing !
man needs to cover 9 meters behind the entrance door of a train when the
train begins to take motion from rest with uniform acceleration of 2m/s^2
but sir accelaration is opposite to the direction of motion so sir accelaration
negative which = -2m/s^2
now sir we will use equation of motion to find the speed
as V^2 = U^@ + 2a s
which means v = 0 U = u a = -2m/s^2 and s = 9
0 - u^2 = -2 *2 * 9
which means
u^2 = 36 and we get = 6 m/s
HOPE THIS HELPS YOU SIR ,
regards brainly helper
we will solve this question with the concept of relative motion sir , now follow
my steps sir what i am doing !
man needs to cover 9 meters behind the entrance door of a train when the
train begins to take motion from rest with uniform acceleration of 2m/s^2
but sir accelaration is opposite to the direction of motion so sir accelaration
negative which = -2m/s^2
now sir we will use equation of motion to find the speed
as V^2 = U^@ + 2a s
which means v = 0 U = u a = -2m/s^2 and s = 9
0 - u^2 = -2 *2 * 9
which means
u^2 = 36 and we get = 6 m/s
HOPE THIS HELPS YOU SIR ,
regards brainly helper
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Answer:mark the brainest plz
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