Question

please help me in solving the sum

(n+2)!/(n+1)!​

Answer 1

(n+2)

Step-by-step explanation:

(n+2)!= (n+2)(n+1)........(3)(2)(1)-eq ®

(n+1)!= (n+1)(n)...........(3)(2)(1) -eq©

eq®÷eq©. = (n+2)

Answer 2

I'm not a math student but I noticed a pattern here, let's say you have 4!

It is equal to 4×3×2×1

So if you have n!

It is n×(n-1)×(n-2)...1

So here (n+2)!=(n+2)(n+1)....1

Now (n+1)×n...1=(n+1)!

According to question, (n+2)!/(n+1)!=n+2

As all other terms cancel out