Math, asked by fattusinghsolankidmd, 8 months ago

please help me in solving this question​

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Answered by sdhanabagyamsdhanaba
1

Answer:

HOPE IT HELPS U

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Answered by rithwikeswari
0

Answer:

kx²-3√2x+4√2=0

D=b²-4ac

0=(-3√2)² -4×k×4√2

0=18-16√2k

0=2(9-8√2k)

0=9-8√2k

-9=-8√2k

9=8√2k

9/8√2=k

k = 9 \div 8 \sqrt{2}k=9÷8

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