please help me in solving this sum
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Step-by-step explanation:
diagonals in a rhombus are perpendicular bisector to each other
and all sides are equal
area of rhombus is 1/2 d1 d2 = 1/2 6 8 = 24
area of OCD = 24/4 = 6
area is 1/2 * b * h = 6
1/2 * OD OC = 6
Sin OCD = 0D / CD
in ACD ;
AREA = 1/2 AD DC
12 = 1/2 CD²
CD = √24 S0 sin ocd = 4 / 2 √6
= 2/√6
= √2/3
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