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Qn 5.
Three consecutive integers: n, n+2, n+4.
Sum = 3 n + 6 = 0. So n = -2.
The integers are : -2, 0, 2.
Qn 6.
Consecutive odd integers: 2n+1, 2n+3
Given (2n+1)*2/5 - (2n+3)*2/9 = 4
(18n + 9 - 10 n -15)/45 = 2
8 n = 96
n = 12.
Consecutive odd integers : 25, 27.
Three consecutive integers: n, n+2, n+4.
Sum = 3 n + 6 = 0. So n = -2.
The integers are : -2, 0, 2.
Qn 6.
Consecutive odd integers: 2n+1, 2n+3
Given (2n+1)*2/5 - (2n+3)*2/9 = 4
(18n + 9 - 10 n -15)/45 = 2
8 n = 96
n = 12.
Consecutive odd integers : 25, 27.
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