please help me in this graph.And please give a step by step explanation.
1.What is the acceleration of particle in portion ab and bc.
2.What is total distance of the particle.
3.What is average velocity of the particle.
Answers
According to the given velocity time graph we are asked to solve some questions.
Knowledge required:
• In a velocity time graph, the slope of graph tell us about the acceleration. If the slope is high then the acceleration is positive, if the solve is low then the acceleration is negative and if the slope is parallel to time axis then there is no acceleration taking place!
• In the velocity time graph the distance or displacement can be founded by the area under the curve!
Required solution:
a) Acceleration of the given partical in portion ab and bc
In portion ab
Explanation: If the slope of Velocity Time graph is parallel to time axis then the acceleration is always zero as there is no change in velocity as acceleration is the term that tell us about the change in velocity with respect to time.
In portion bc
b) Total distance of the particle
Firstly finding area of 1st triangle
Finding area of rectangle 1st
Finding area of trapezium 1st
Finding area of 1st triangle
Now let us calculate distance
c) Average velocity of the particle
Explanation: We know that average velocity = Total distance/Total time Therefore,
- Total distance = 4000 m
- Total time = 100 seconds
Henceforth,
→ Average velocity = Total distance/Total time
→ Average velocity = 4000/100
→ Average velocity = 40 m/s