Please help me in this MATHS QUESTION ....
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hey,
This is pretty easy as I solved this question today in Allen. .
so,
(x^a/x^b)^a+b = (x^a-b)^a+b × (x^b-c)^b+c× (x^c-a)^c+a
now as per the law..
(a-b )(a+b) =a^2 - b^2
so,
x^(a^2-b^2) × x^(b^2-c^2) × x^(c^2 -a^2)
= x^(a^2-b^2+b^2-c^2+c^2-a^2)
x^0
=1..
Hope it helps
This is pretty easy as I solved this question today in Allen. .
so,
(x^a/x^b)^a+b = (x^a-b)^a+b × (x^b-c)^b+c× (x^c-a)^c+a
now as per the law..
(a-b )(a+b) =a^2 - b^2
so,
x^(a^2-b^2) × x^(b^2-c^2) × x^(c^2 -a^2)
= x^(a^2-b^2+b^2-c^2+c^2-a^2)
x^0
=1..
Hope it helps
Anonymous:
Thanks ...
Answered by
2
Hope you understand my handwriting...
Thanks
Thanks
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