Question

please help me in this question ​

Answer 1

Answer:

triangke pqs =55+60+x=180

115 +x=180

180-115=a

a=b OPP angles are equl

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Answer 2

Answer:

a = 65°

b = 115°

c = 25°

Step-by-step explanation:

In ∆ PQS

a+ 60° + 55° =180° ( sum of all the angle of a ∆ is always 180°)

a + 115° = 180°

a= 180° - 115°

a = 65°

For line QS

a + b = 180° (Linear pair angle)

65° + b = 180°

b = 115°

In ∆PSR

40° + b + c = 180°

40° + 115° + c = 180°

155° + c = 180°

c = 180° - 155°

c = 25°