Question

Please help me in this question​

Answer 1

In △ABC,

(1) M is the mid point of AB and

MD∥BC

D is the mid point of AC

(2) As MD∥BC &

AC is transversal

∠MDC+∠BCD=180∘

∠MDC+90∘=180∘⇒∠MDC=90∘⇒MD⊥AC

(3) In △AMD and △CMD

AD=CD

∠ADM=∠CDM

DM=DM

△AMD≅△CMD

AM=CM⇒AM=½AB⇒CM=AM=½AB

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Answer 2

Step-by-step explanation:

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