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Explanation:
The velocity field associated with a fluid flow given by 2 u 20y , v 20xy, w 0. Find the
acceleration, the angular velocity and the vorticity vector at the point (1,-1,2).
The acceleration vector is given by
Dq q q q q a uvw
Dt t x y z
2
2 32
Thus, a 20y ( 20yj) 20xy(40yi 20xj) ˆ ˆˆ
ˆ ˆ = 800xy i 400(y x y)j.
Thus at (1,-1, 2), ˆ 2 a is given by a 800im / s
The vorticityvector is given by
xyz ( , , )
wv uw vu = , , yz zx xy
= 0, 0, ( 20y 40y) =(0 ,0, 60y)
Hence, at z (1, -1, 2), (0, 0, 60).
Thus, the x and y component of vorticity vector vanish whilst the z-component of vorticity
vector is given by z
ˆ ˆ k 60krad / s. Thus, the angular velocity at
(1, 1, 2) is given by (0, 0, 30).
Application of continuity equation
2. Water flows at a uniform speed of 5m / s into a nozzle whose diameter reduces from