Math, asked by apm2mishra, 1 year ago

Please help me in this question:

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Answered by SaiNikhilHarry

logically.......
maximum capacity of basket is 100 eggs right.
Then by selling 3 eggs at a time the maximum number at which the eggs remain 1 to be left is 100(eggs in Basket ).you got it !only one will be left.....
But if you sell 4 at a time this doesn't hold ...that means no egg wil be left..
by verification and logical process u can easily find that when basket is with 97 eggs there will be ONE egg left for both cases.i.e 3 at a time and 4 at a time.....
so the maximum no.of eggs in Basket to hold both the cases is 97....

Hole this helps u...
if u haven't seems like this helpful. .I'm sorry for that...

SaiNikhilHarry: will look after it

apm2mishra: Fine..

SaiNikhilHarry: ok it's not possible to edit answer

SaiNikhilHarry: let me tell u

SaiNikhilHarry: by question it is clear that the eggs in basket must be a multiple of 7....right. ..

SaiNikhilHarry: so multiples of 7....are possibilities and by dividing them by 3 and 4...the number where u can find remainder 1 is 49

SaiNikhilHarry: u got it?

SaiNikhilHarry: hey.........if u have not cleared type the question in search bo the same question was previously asked once............

SaiNikhilHarry: check once

SaiNikhilHarry: thank you

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