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Sin(a+b-c) = 1/2
we know Sin30° = 1/2
So , a+b-c = 30°------(1)
then,
Cos(b+c-a) = 1/√2
Cos45° = 1√2
so , b+c-a = 45°-----(2)
we already know in a triangle a + b + c = 180°------(3)
subtracting 1 from 3
a + b + c - a - b + c = 180-30
=> 2C = 150
=> C = 75°
subtracting 2 from 3
a+b+c - b -c + a = 180-45°
2a = 135
a = 67.5
using these equations u can easily find a , b ,c
we know Sin30° = 1/2
So , a+b-c = 30°------(1)
then,
Cos(b+c-a) = 1/√2
Cos45° = 1√2
so , b+c-a = 45°-----(2)
we already know in a triangle a + b + c = 180°------(3)
subtracting 1 from 3
a + b + c - a - b + c = 180-30
=> 2C = 150
=> C = 75°
subtracting 2 from 3
a+b+c - b -c + a = 180-45°
2a = 135
a = 67.5
using these equations u can easily find a , b ,c
yamini74:
can you tell me the full ans with pic
wait i will edit the answer
OK
by the way i was going to sleep
oh...
OK its fine
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