Question

PLEASE HELP ME IN THIS QUESTION
Q-- For what value of 'n' are the nth term of two APs 63,65,67,..... and 3,10,17,..... are equal?

Answer 1

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Solution:--


in first AP
a=63,d=2
nth term=63+(n-1)2=63+2n-2=2n+61

in second AP
a=3,d=7
nth term=3+(n-1)7=3+7n-7=7n-4

7n-4=2n+61
5n=65
n=65/5=13
thus, n=13

Answer 2

☆☆hey dude your ans is here ⬇ ⬇

let's start :--


suppose for the nth value of the given two AP s ....nth terms are equal.


then ,

--) 63 + ( n- 1 ) 2 = 3 + ( n - 1 ) 7
--) 63 + 2n - 2 = 3 + 7n - 7
--) 61 + 2n = 7n - 4
--) -5n = -65
--) n = ( -65/-5)= 13.

hence required n th term is 13 .


☺ ☆☆ I hope this ans would helpful to you.

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