Math, asked by Manisharouth, 1 year ago

please help me it's very much important.

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Answered by SushanthBuddhala

Maybe we should substitute (x-2) in x

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Answered by tanzz80

1. f(x)=2x^3-7x^2+3
put x-2=0
x=2
f(2)=2(2)^3-7(2)^2+3
=16-28+3
=9

3.f(x)=3x^3-7x^2+4x+11
put 2x+1=0
x= -1/2
f(-1/2)=3(-1/2)^3-7(-1/2)^2+4(-1/2)+11
=-3/8-7/4-2+11
= -3-14-88/8
=-17-88/8
=-105/8

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Manisharouth: Thanksgiving me answers.

Manisharouth: what is your name.

tanzz80: want the other two?

Manisharouth: yes I want.

tanzz80: done 2nd and 3rd

Manisharouth: thanks again.

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