Question

please help me koi bhi answer nai de raha kaay kisi ko nai aata?? Please explain step by step with method ​

Answer 1

16. (2)100m,100m

17. (3)50m,50m

Q16) Area under the vt graph gives displacement.

therefore ,

from 0 to 15s, the area is = area of a triangle + area of a square

= (1/2*10*15)+(5^2)

=100m

Therefore displacement is 100m

And in vt graph the velocity is positive then the distance is equal to the displacement,

therefore distance is also 100m.

SAME WAY,we can find the area under 10 -20s

which will be, area of a square + area of a triangle

=25+25

displacement=50m

And as the distance is equal to the displacement,

answer is 50m,50m.

I HOPE THIS HELPS