Question

please help me out
find the value of x in
$\sqrt{x + 2 \sqrt{x + 2 \sqrt{x + 2 \sqrt{3x} } } } = x$
I promise that I will mark you as the brainliest answer ​

Answer 1

Answer:

If the expression x=sqrt(2+sqrt(2+sqrt(2+sqrt(2+...) extends to an infinite number of roots and converges to a positive number x, what is x?

A- Sqrt(3)

B- 2

C- 1+sqrt(2)

D- 1+sqrt(3)

E- 2*sqrt(3)

--> , as the expression under square root extends infinitely then expression in brackets would equal to itself so we can rewrite given expression as . Square both sides --> or . As given that then only one solution is valid: .

Answer: B.

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