Math, asked by smithfashionbkp, 9 months ago

please help me out if u help me I will mark u as brain list and if it is possible for u do it in a paper
Thank u so much who is helping please show full method and I need all the questions ​

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Answers

Answered by missbrilliant22
19

Answer:

2)y=50degree ..

Solution -

Y+Y+10+Y+20=180DEGREE (LINEAR PAIR)

3Y+30=180DEGREE

3Y=150DEGREE

Y=50DEGREE

Answered by Tomboyish44
55

Question (a)

On line AB,

➝ ∠AOC + ∠COE + ∠EOB = 180° (Straight line)

➝ 4b + 75° + b = 180°

➝ 5b + 75° = 180°

➝ 5b = 180° - 75°

➝ 5b = 105°

➝ b = 105/5°

b = 21°

On line CD,

➝ ∠AOC + ∠AOD = 180° (Linear pair)

➝ 4b + 2c = 180°

➝ 4(21)° + 2c = 180°

➝ 84° + 2c = 180°

➝ 2c = 180° - 84°

➝ 2c = 96°

➝ c = 96/2°

c = 48°

On line AB,

➝ ∠AOD + ∠DOB = 180° (Linear pair)

➝ 2c + a = 180°

➝ 2(48)° + a = 180°

➝ 96° + a = 180°

➝ a = 180° - 96°

a = 84°

Question (b)

On line AB:

➝ ∠AOC + ∠COD + ∠DOB = 180° (Straight line)

➝ y + y + 10° + y + 20° = 180°

➝ 3y + 30° = 180°

➝ 3(y + 10°) = 180°

➝ y + 10° = 180/3°

➝ y + 10° = 60°

➝ y = 60° - 10°

y = 50°

(Refer to the attachments for markings)

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