Question

Please help me out please

Answer 1

From the question it is given that, ∠1 = (2a + b)o and ∠6 = (3a – b)o Since ∠5 and ∠6 these two forms a linear pair Then, ∠5 = (180-3a + b)o … [equation 1] ∠5 = ∠1 = (180-3a + b)o [Because Corresponding angles] …equation (2) On equating equation (1) and equation (2) we get, 2a + b = 180-3a + b 5a = 180 a = 360 Since ∠1 and ∠2 forms a linear pair so ∠2 = 1800– 2a-bRead more on Sarthaks.com - https://www.sarthaks.com/791252/in-fig-pq-rs-if-1-2a-b-and-6-3a-b-then-the-measure-of-2-in-terms-of-b-is