Question

Please help me out with this one


A negatively-charged pion,whose mass is 273 times the mass of electrons moves in a circular orbit around a proton .it is a pi-mesic hydrogen atom.How many revolutions will the pion make during its lifetime of 10^-8s in the ground state of the atom?

ans is 1.8×10^10

Answer 1

hello mate!!!!!
thanks for asking me this question....... the right answer is.......
the revolution will the poin make during its lifetime of 10^-8s in the ground state of the atom is ..
"" "" "1.8×10^10==18 000 000 000
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Answer 2

Explanation:

detailed solution first time...

Arup Chakraborty (Physics )

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