Question

Please help me out with this question.

Answer 1

$\huge\bf{Answer:-}$

Refer the attachment.©

Answer 2

Answer:

Let A'CB represents the tree before it broken at the point C and let the top A' touches the ground at A after it broke.

The ΔABC is a right angled triangle, right angled at B.

AB=12=12m and BC=5=5m

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Using Pythagoras theorem, In ΔABC

${(AC)}^{2} = {(AB)}^{2} + {(BC)}^{2} \\ \\ {(AC)}^{2} = {(12)}^{2} + {(5)}^{2} \\ \\ {(AC)}^{2} = 144 + 25 \\ \\ {(AC)}^{2} = 169 \\ \\ AC = \sqrt{169} \\ \\ AC = 13$

Hence, the total height of the tree

=AC+CB

=13+5

=18m

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