Question

please help me please

Answer 1

hello users....

solution:-
we know that
perimeter of rectangle = 2(L+b)

Area of rectangle = L × b

perimeter of square = 4a

Area of square = a²

where,
L is length, b is breadth and a is side of square.

here,
According to given;
Length of rectangle (L) = 12 m
and
Area of rectangle = 72 m²

=> L × b = 72

=> b = 72/ L= 72/12 = 6 m

now,
length of wire = perimeter of rectangle

= 2(L + b)
= 2( 12 + 6)
= 2×18 = 36

now,
Length of wire = perimeter of rectangle = perimeter of square

=> 4a = 36

=> a = 9 m

now,
Area of square = a²
= 9² = 81 m²

hence,
perimeter of square = 36 m
and
area of square = 81 m² Answer

✡✡ hope it helps ✡✡

Answer 2

l=12m
area of rectangle =72=l*b
72=12*b
72/12=b
6m=b

now find the perimeter of rectangle because the perimeterof rectangle =lengthof wire
perimeter=2(l+b)
2(12+6)
2(18)
=36m

now the same wire is reshaped to spuare so perimeter will be same so
perimeterof spuare=36m

perimeter=36=4*side
36/4=side
9=side


area of square=side *side
=9*9
$81 {m}^{2}$