please help me please help give me answer
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Possibles outcomes in a single throw of a die is
{1,2,3,4,5,6} = 6
let E = Getting a number less than 3
There are two numbers {1,2} which is less than 3.
so, required probability P(E) = 2/6 = 1/3.
Step-by-step explanation:
I hope it's help you.
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