Question

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Answer 1

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12)ANSWER = ₹481.54

GIVEN:

P = ₹1000
r = 8%
n = 1½years = 3/2 years

TO FIND:

Compound interest

SOLUTION:

A = P[ 1 + ½(r/100)]power 2n

A = 1000[1 + ½(8/100)power 2*3/2

A = 1000[1 + 8/200)³

A = 1000[1 + 0.04]³

A = 1000[1.14]³

A = 1000(1.481544)

A = ₹1481.54

CI = A - P

CI = 1481.54 - 1000

CI = ₹481.54
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7)Answer = ₹2035.02

GIVEN:

P = ₹8000
r = 12½% = 24/2 %
n = 2 years

TO FIND:

Compound interest

SOLUTION:

A = P(1 + r/100) power n

A = 8000(1 + 24/2*100)²

A = 8000(200/200 + 24/200)²

A = 8000(224/200)²

A = 8000(1.12)²

A = 8000(1.2544)

A = ₹10035.02

CI = A - P

CI = 10035.02 - 8000

CI = ₹2035.02
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