Question

please help me solve this guys it's a humble request​

Answer 1

For first figure:

3a = 18

=) a = 6

3a-1 = 2b

=) 18-1 = 2b

=) b = 17÷2

=) b = 8.5

For second figure:

b = 70⁰

[ since alternate angle of angle BCD]

a + b + 75 = 180

=) a+70+75= 180

=) a+ 145 = 180

=) a = 35⁰

Answer 2

Answer:

by tensversal angle dcb= angle b

angle b=70 degree

now,

in triangle abd

75+70+a=180

145+a=180

a=35 degree..... ok......