Question

Please help me solve this question i have term 1 tommorow maths​

Answer 1

Answer:

See the detailed explanation

Step-by-step explanation:

Left hand limit (LHL)

            $=\displaystyle \lim_{x\to 1^-}f(x)=\lim_{x\to 1^-}(1+x^2)=1+1^2=1+1=2$

Right hand limit (RHL)

            $=\displaystyle \lim_{x\to 1^+}f(x)=\lim_{x\to 1^+}(2-x)=2-1=1$

Clearly since LHL $\neq$ RHL $\Rightarrow$ limit $\displaystyle \lim_{x\to 1}f(x)$ does not exist