Question

Please help me solving this .....
I'll mark it brainliest if i hv got the correct answer....​

Answer 1

Answer:

square the term

Step-by-step explanation:

sin

$\sin( \alpha) + 1 \div \sin\alpha = 2 \\ (sin( \alpha ) +1 \div \sin( \alpha )) {2} = 4 \\ \\ \sin( \alpha { +}^{2} ) + 1 \div \sin( \alpha {?}^{2} ) + 2 = 4 \\ \sin( \alpha {?}^{2} ) + 1 \div \sin( \alpha {?}^{2} ) = 4 - 2 \\ = 2$