Math, asked by lukasandrius09, 11 months ago

please help me! This is impossible!

Two candles of equal height start to burn simultaneously. One of the candles is thicker than the other one and burns out in 4 hours, while the thinner one burns out in 2 hours. Both of the candles are extinguished after some time, and the remaining height of the thicker candle is now 3 times as long as the thinner one. How many minutes were the candles burning for?

Answers

Answered by Archita893
2

Answer:

96 minutes !

Solution refers to the attachment above !

Attachments:
Answered by usreeraj
0

Answer:

96 min

Step-by-step explanation:

Time to burn completely

Thick Candle = 4h

Thin Candle = 2h

Candle burn for 1 min:

Thick Candle = 1/(4*60)

Thin Candle = 1/(2*60)

After x min

Thick Candle = x/240

Thin Candle = x/120

height remaining

Thick Candle = 1 - x/240

Thin Candle = 1 - x/120

1 - x/240 = 3 (1 - x/120)

=> 1 - x/240 = 3 - x/40

=> x/40 -x/240 = 2

=> 5x/240 = 2

=> x = 96

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