Question

please help me

this sum is difficult

I am in 9th class

please help me

I will mark you brainlist ​

Answer 1

Answer:

of which school please let me......

Answer 2

Step-by-step explanation:

putting x =1

(1)^3 -6(1)^2+11(1)-6=0

one root is (x-1)

divide whole eqn by (x-1)

(x-1) | x^3 -6x^2 + 11x -6 | X^2 -5x +6

x^3 -x^2

=======

-5x^2 +11x-6

-5x^2+5x

========

6x-6

6x-6

=====

0

so eqn is x^2-5x+6=0

x^2-2x-3x+6=0

(x-2)(x-3)=0

so the roots are- 1 ,-2,-3