Question

X^2+2px-3qx-6pq=0 solve for X value for quadratic equation​

Answer 1

Answer:

Step-by-step explanation:

${x}^2+2px-3qx=6pq$

$=> {x}^2+x(2p-3q)=6pq$

$=> {4x}^2+4x(2p-3q)=24pq$

$=> {2x}^2+2.2x(2p-3q)+(2p-3q)^2=24pq+(2p-3q)^2$

$=> (2x+2p-3q)^2=24pq+(2p)^2-2.2p.3q+(-3q)^2$

$=> (2x+2p-3q)^2= 24pq+4p^2-12pq+9q^2$

$=> (2x+2p-3q)^2=12pq+4p^2+9q^2$

$=> (2x+2p-3q)^2= (2p)^2+(3q)^2+2×2p×3q$

$=> (2x+2p-3q)^2= (2p+3q)^2$

$=> 2x+2p-3q= +- (2p+3q)$

$=> 2x= +- (2p+3q)-(2p-3q)$

$=> {2p-2p+3q+3q/2\:or \:-2p-2p-3q-3q/2}$

$\:\:\:\: {=6q/2=3q}\:or\:{-4p/2=-2p}$

•°• The value of x is 3q or -2p

Answer 2

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